Jee Main
Units And Measurements
JEE Main 2026 (Online) 6th April Morning Shift
MCQ+4 / -12026
The potential energy of a particle changes with distance $x$ from a fixed origin as $V=\frac{A \sqrt{x}}{x+B}$, where $A$ and $B$ are constant with appropriate dimensions. The dimensions of $A B$ are $\_\_\_\_$