Jee Main
Simple Harmonic Motion
JEE Main 2026 (Online) 24th January Morning Shift
MCQ+4 / -12026
A spring of force constant $15 \mathrm{~N} / \mathrm{m}$ is cut into two pieces. If the ratio of their length is $1: 3$, then the force constant of smaller piece is $\_\_\_\_$ $\mathrm{N} / \mathrm{m}$.