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JEE Main 2026 (Online) 4th April Morning Shift

INTEGER+4 / -12026

The surface tension of a soap solution is $3.5 \times 10^{-2} \mathrm{~N} / \mathrm{m}$. The work required to increase the radius of a soap bubble from 1 cm to 2 cm is $\alpha \times 10^{-6} \mathrm{~J}$. The value of $\alpha$ is $\_\_\_\_$ .


\((\pi=22 / 7)\)

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