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Gravitation

JEE Main 2026 (Online) 22nd January Morning Shift

MCQ+4 / -12026

Net gravitational force at the center of a square is found to be $F_1$ when four particles having mass $M, 2 M, 3 M$ and $4 M$ are placed at the four corners of the square as shown in figure and it is $F_2$ when the positions of $3 M$ and $4 M$ are interchanged. The ratio $\frac{F_1}{F_2}$ is $\frac{\alpha}{\sqrt{5}}$. The value of $\alpha$ is $\_\_\_\_$ .

JEE Main 2026 (Online) 22nd January Morning Shift Physics - Gravitation Question 9 English

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