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Trigonometric Ratio And Identites

JEE Main 2026 (Online) 23rd January Evening Shift

MCQ+4 / -12026

Let $\frac{\pi}{2}<\theta<\pi$ and $\cot \theta=-\frac{1}{2 \sqrt{2}}$. Then the value of


\(\sin \left(\frac{15 \theta}{2}\right)(\cos 8 \theta+\sin 8 \theta)+\cos \left(\frac{15 \theta}{2}\right)(\cos 8 \theta-\sin 8 \theta)\)


is equal to :

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