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JEE Main 2026 (Online) 2nd April Morning Shift

INTEGER+4 / -12026

If $\sum\limits_{k=1}^{n} a_k = 6 n^3$, then $\sum\limits_{k=1}^{6} \left( \frac{a_{k+1} - a_k}{36} \right)^2$ is equal to ________.

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