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Quadratic Equation And Inequalities

JEE Main 2026 (Online) 21st January Evening Shift

MCQ+4 / -12026
Let $\alpha$ and $\beta$ be the roots of the equation $x^2+2 a x+(3 a+10)=0$ such that $\alpha<1<\beta$. Then the set of all possible values of $a$ is :

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