Jee Main
Parabola
JEE Main 2026 (Online) 21st January Evening Shift
MCQ+4 / -12026
Let one end of a focal chord of the parabola $y^2 = 16x$ be $(16,16)$. If $P(\alpha,\ \beta)$ divides this focal chord internally in the ratio $5:2$, then the minimum value of $\alpha + \beta$ is equal to:
