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Limits Continuity And Differentiability

JEE Main 2026 (Online) 28th January Morning Shift

MCQ+4 / -12026

The value of


\(\lim\limits_{x \rightarrow 0} \frac{\log _e\left(\sec (e x) \cdot \sec \left(e^2 x\right) \cdot \ldots \cdot \sec \left(e^{10} x\right)\right)}{e^2-e^{2 \cos x}}\)


is equal to

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