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JEE Main 2026 (Online) 5th April Evening Shift

MCQ+4 / -12026

Let $z_1, z_2 \in \mathbb{C}$ be the distinct solutions of the equation $z^2+4 z-(1+12 i)=0$.


Then $\left|z_1\right|^2+\left|z_2\right|^2$ is equal to :


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