Jee Main
Binomial Theorem
JEE Main 2026 (Online) 4th April Evening Shift
MCQ+4 / -12026
In the expansion of $\left(9 x-\frac{1}{3 \sqrt{x}}\right)^{18}, x>0$, if the term independent of $x$ is (221)k, then k is equal to:
Jee Main
JEE Main 2026 (Online) 4th April Evening Shift
In the expansion of $\left(9 x-\frac{1}{3 \sqrt{x}}\right)^{18}, x>0$, if the term independent of $x$ is (221)k, then k is equal to: