Jee Main
Application Of Derivatives
JEE Main 2026 (Online) 22nd January Morning Shift
MCQ+4 / -12026
Let $f(x)=x^{2025}-x^{2000}, x \in[0,1]$ and the minimum value of the function $f(x)$ in the interval $[0,1]$ be $(80)^{80}(n)^{-81}$. Then $n$ is equal to
