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Application Of Derivatives

JEE Main 2026 (Online) 22nd January Morning Shift

MCQ+4 / -12026

Let $f(x)=x^{2025}-x^{2000}, x \in[0,1]$ and the minimum value of the function $f(x)$ in the interval $[0,1]$ be $(80)^{80}(n)^{-81}$. Then $n$ is equal to


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