Jee Main
Ionic Equilibrium
JEE Main 2026 (Online) 2nd April Morning Shift
MCQ+4 / -12026
The solubility product constants of $\mathrm{Ag_2CrO_4}$ and $\mathrm{AgBr}$ are $32x$ and $4y$ respectively at 298 K.
The value of \(\left( \frac{\text{molarity of } \mathrm{Ag_2CrO_4}}{\text{molarity of } \mathrm{AgBr}} \right)\) can be expressed as :