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Alcohols Phenols And Ethers

JEE Main 2026 (Online) 5th April Morning Shift

INTEGER+4 / -12026

One mole of phenol is treated with dilute $\mathrm{HNO}_3$ at 298 K to give a mixture of products. The mixture is separated by steam distillation. The steam volatile compound $(\mathrm{X})$ is separated. The increase in percentage of oxygen in $(\mathrm{X})$ with respect to phenol is $\_\_\_\_$ $\times 10^{-1} \%$


(Given molar mass in $\mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{~N}: 14, \mathrm{O}: 16$ )

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