Jee Main
Simple Harmonic Motion
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ+4 / -12025
A particle is subjected to two simple harmonic motions as :
\(x_1=\sqrt{7} \sin 5 \mathrm{tcm}\)
and $x_2=2 \sqrt{7} \sin \left(5 t+\frac{\pi}{3}\right) \mathrm{cm}$
where $x$ is displacement and $t$ is time in seconds.
The maximum acceleration of the particle is $x \times 10^{-2} \mathrm{~ms}^{-2}$. The value of $x$ is :
