Jee MainApplication Of DerivativesJEE Main 2025 (Online) 3rd April Evening ShiftMCQ+4 / -12025ENHIThe shortest distance between the curves $y^2=8 x$ and $x^2+y^2+12 y+35=0$ is: A$2 \sqrt{3}-1$B$2 \sqrt{2}-1$C$3 \sqrt{2}-1$D $\sqrt{2}$Check AnswerClear SelectionReveal AnswerShow Explanation