Laws Of Motion

A block of mass \(5 \mathrm{~kg}\) is placed on a rough inclined surface as shown in the figure. If \(\overrightarrow{F_1}\) is the force required to just move the block up the inclined plane and \(\overrightarrow{F_2}\) is the force required to just prevent the block from sliding down, then the value of \(\left|\overrightarrow{F_1}\right|-\left|\overrightarrow{F_2}\right|\) is : [Use \(\left.\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right]\)