Atoms And Nuclei

The disintegration energy \(Q\) for the nuclear fission of \({ }^{235} \mathrm{U} \rightarrow{ }^{140} \mathrm{Ce}+{ }^{94} \mathrm{Zr}+n\) is
_______ \(\mathrm{MeV}\).

Given atomic masses of \({ }^{235} \mathrm{U}: 235.0439 u ;{ }^{140} \mathrm{Ce}: 139.9054 u, { }^{94} \mathrm{Zr}: 93.9063 u ; n: 1.0086 u\),
Value of \(c^2=931 \mathrm{~MeV} / \mathrm{u}\).