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JEE Main 2024 (Online) 9th April Evening Shift

MCQ+4 / -12024

The energy released in the fusion of \(2 \mathrm{~kg}\) of hydrogen deep in the sun is \(E_H\) and the energy released in the fission of \(2 \mathrm{~kg}\) of \({ }^{235} \mathrm{U}\) is \(E_U\). The ratio \(\frac{E_H}{E_U}\) is approximately:
(Consider the fusion reaction as \(4_1^1H+2 \mathrm{e}^{-} \rightarrow{ }_2^4 \mathrm{He}+2 v+6 \gamma+26.7 \mathrm{~MeV}\), energy released in the fission reaction of \({ }^{235} \mathrm{U}\) is \(200 \mathrm{~MeV}\) per fission nucleus and \(\mathrm{N}_{\mathrm{A}}= 6.023 \times 10^{23})\)

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