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Parabola

JEE Main 2024 (Online) 27th January Morning Shift

MCQ+4 / -12024
If the shortest distance of the parabola $y^2=4 x$ from the centre of the circle $x^2+y^2-4 x-16 y+64=0$ is $\mathrm{d}$, then $\mathrm{d}^2$ is equal to :

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