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Matrices And Determinants

JEE Main 2024 (Online) 29th January Morning Shift

MCQ+4 / -12024

Let \(\mathrm{A}\) be a square matrix such that \(\mathrm{AA}^{\mathrm{T}}=\mathrm{I}\). Then \(\frac{1}{2} A\left[\left(A+A^T\right)^2+\left(A-A^T\right)^2\right]\) is equal to

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