Jee Main
Matrices And Determinants
JEE Main 2024 (Online) 29th January Morning Shift
MCQ+4 / -12024
Let \(\mathrm{A}\) be a square matrix such that \(\mathrm{AA}^{\mathrm{T}}=\mathrm{I}\). Then \(\frac{1}{2} A\left[\left(A+A^T\right)^2+\left(A-A^T\right)^2\right]\) is equal to
