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Indefinite Integrals

JEE Main 2024 (Online) 27th January Evening Shift

MCQ+4 / -12024

\(\text { The integral } \int \frac{\left(x^8-x^2\right) \mathrm{d} x}{\left(x^{12}+3 x^6+1\right) \tan ^{-1}\left(x^3+\frac{1}{x^3}\right)} \text { is equal to : }\)

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