Jee Main
Differentiation
JEE Main 2024 (Online) 9th April Morning Shift
MCQ+4 / -12024
Let \(f(x)=a x^3+b x^2+c x+41\) be such that \(f(1)=40, f^{\prime}(1)=2\) and \(f^{\prime \prime}(1)=4\). Then \(a^2+b^2+c^2\) is equal to:
Jee Main
JEE Main 2024 (Online) 9th April Morning Shift
Let \(f(x)=a x^3+b x^2+c x+41\) be such that \(f(1)=40, f^{\prime}(1)=2\) and \(f^{\prime \prime}(1)=4\). Then \(a^2+b^2+c^2\) is equal to: