Jee Main
Binomial Theorem
JEE Main 2024 (Online) 8th April Evening Shift
MCQ+4 / -12024
If the term independent of \(x\) in the expansion of \(\left(\sqrt{\mathrm{a}} x^2+\frac{1}{2 x^3}\right)^{10}\) is 105 , then \(\mathrm{a}^2\) is equal to :
Jee Main
JEE Main 2024 (Online) 8th April Evening Shift
If the term independent of \(x\) in the expansion of \(\left(\sqrt{\mathrm{a}} x^2+\frac{1}{2 x^3}\right)^{10}\) is 105 , then \(\mathrm{a}^2\) is equal to :