Work Power And Energy

If the maximum load carried by an elevator is \(1400 \mathrm{~kg}\) ( \(600 \mathrm{~kg}\) - Passengers + 800 \(\mathrm{kg}\) - elevator), which is moving up with a uniform speed of \(3 \mathrm{~m} \mathrm{~s}^{-1}\) and the frictional force acting on it is \(2000 \mathrm{~N}\), then the maximum power used by the motor is __________ \(\mathrm{kW}\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)