Jee Main
Rotational Motion
JEE Main 2023 (Online) 29th January Evening Shift
INTEGER+4 / -12023
A particle of mass 100 g is projected at time t = 0 with a speed 20 ms\(^{-1}\) at an angle 45\(^\circ\) to the horizontal as given in the figure. The magnitude of the angular momentum of the particle about the starting point at time t = 2s is found to be \(\mathrm{\sqrt K~kg~m^2/s}\). The value of K is ___________.
(Take g = 10 ms\(^{-2}\))
