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Rotational Motion

JEE Main 2023 (Online) 1st February Evening Shift

INTEGER+4 / -12023

Moment of inertia of a disc of mass '\(M\)' and radius '\(R\)' about any of its diameter is \(\frac{M R^{2}}{4}\). The moment of inertia of this disc about an axis normal to the disc and passing through a point on its edge will be, \(\frac{x}{2}\) MR\(^{2}\). The value of \(x\) is ___________.

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