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Laws Of Motion

JEE Main 2023 (Online) 8th April Morning Shift

MCQ+4 / -12023

At any instant the velocity of a particle of mass \(500 \mathrm{~g}\) is \(\left(2 t \hat{i}+3 t^{2} \hat{j}\right) \mathrm{ms}^{-1}\). If the force acting on the particle at \(t=1 \mathrm{~s}\) is \((\hat{i}+x \hat{j}) \mathrm{N}\). Then the value of \(x\) will be:

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