Vector Algebra

Let \(\vec{a}\) and \(\vec{b}\) be two vectors such that \(|\vec{a}|=\sqrt{14},|\vec{b}|=\sqrt{6}\) and \(|\vec{a} \times \vec{b}|=\sqrt{48}\). Then \((\vec{a} \cdot \vec{b})^{2}\) is equal to ___________.