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JEE Main 2023 (Online) 1st February Evening Shift

MCQ+4 / -12023

Let \(9=x_{1} < x_{2} < \ldots < x_{7}\) be in an A.P. with common difference d. If the standard deviation of \(x_{1}, x_{2}..., x_{7}\) is 4 and the mean is \(\bar{x}\), then \(\bar{x}+x_{6}\) is equal to :

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