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Limits Continuity And Differentiability

JEE Main 2023 (Online) 8th April Evening Shift

MCQ+4 / -12023

If \(\alpha > \beta > 0\) are the roots of the equation \(a x^{2}+b x+1=0\), and \(\lim_\limits{x \rightarrow \frac{1}{\alpha}}\left(\frac{1-\cos \left(x^{2}+b x+a\right)}{2(1-\alpha x)^{2}}\right)^{\frac{1}{2}}=\frac{1}{k}\left(\frac{1}{\beta}-\frac{1}{\alpha}\right), \text { then } \mathrm{k} \text { is equal to }\) :

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