Jee Main
Limits Continuity And Differentiability
JEE Main 2023 (Online) 24th January Morning Shift
MCQ+4 / -12023
\(\mathop {\lim }\limits_{t \to 0} {\left( {{1^{{1 \over {{{\sin }^2}t}}}} + {2^{{1 \over {{{\sin }^2}t}}}}\, + \,...\, + \,{n^{{1 \over {{{\sin }^2}t}}}}} \right)^{{{\sin }^2}t}}\) is equal to
