Jee Main
Hyperbola
JEE Main 2023 (Online) 25th January Evening Shift
MCQ+4 / -12023
Let T and C respectively be the transverse and conjugate axes of the hyperbola \(16{x^2} - {y^2} + 64x + 4y + 44 = 0\). Then the area of the region above the parabola \({x^2} = y + 4\), below the transverse axis T and on the right of the conjugate axis C is :