Jee Main
Binomial Theorem
JEE Main 2023 (Online) 15th April Morning Shift
MCQ+4 / -12023
Let $\left(a+b x+c x^{2}\right)^{10}=\sum\limits_{i=0}^{20} p_{i} x^{i}, a, b, c \in \mathbb{N}$.
If $p_{1}=20$ and $p_{2}=210$, then
$2(a+b+c)$ is equal to :
If $p_{1}=20$ and $p_{2}=210$, then
$2(a+b+c)$ is equal to :