Solutions

What weight of glucose must be dissolved in \(100 \mathrm{~g}\) of water to lower the vapour pressure by \(0.20 \mathrm{~mm} ~\mathrm{Hg}\) ?

(Assume dilute solution is being formed)

Given : Vapour pressure of pure water is \(54.2 \mathrm{~mm} ~\mathrm{Hg}\) at room temperature. Molar mass of glucose is \(180 \mathrm{~g} \mathrm{~mol}^{-1}\)