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Practical Organic Chemistry

JEE Main 2023 (Online) 13th April Evening Shift

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\(0.400 \mathrm{~g}\) of an organic compound \((\mathrm{X})\) gave \(0.376 \mathrm{~g}\) of \(\mathrm{AgBr}\) in Carius method for estimation of bromine. \(\%\) of bromine in the compound \((\mathrm{X})\) is ___________.


(Given: Molar mass \(\mathrm{AgBr=188~g~mol^{-1}}\)


\(\mathrm{Br}=80 \mathrm{~g} \mathrm{~mol}^{-1}\))

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