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JEE Main 2023 (Online) 25th January Morning Shift

MCQ+4 / -12023

Compound A reacts with NH\(_4\)Cl and forms a compound B. Compound B reacts with H\(_2\)O and excess of CO\(_2\) to form compound C which on passing through or reaction with saturated NaCl solution forms sodium hydrogen carbonate. Compound A, B and C, are respectively :

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