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Electrochemistry

JEE Main 2023 (Online) 10th April Morning Shift

INTEGER+4 / -12023

\(\mathrm{FeO_4^{2 - }\buildrel { + 2.2V} \over \longrightarrow F{e^{3 + }}\buildrel { + 0.70V} \over \longrightarrow F{e^{2 + }}\buildrel { - 0.45V} \over \longrightarrow F{e^0}}\)


\(E_{FeO_4^{2 - }/F{e^{2 + }}}^\theta\) is \(x \times {10^{ - 3}}\) V. The value of \(x\) is _________

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