Jee Main
Laws Of Motion
JEE Main 2022 (Online) 27th June Evening Shift
INTEGER+4 / -12022
A mass of 10 kg is suspended vertically by a rope of length 5 m from the roof. A force of 30 N is applied at the middle point of rope in horizontal direction. The angle made by upper half of the rope with vertical is \(\theta\) = tan\(-\)1 (x \(\times\) 10\(-\)1). The value of x is ____________.
(Given, g = 10 m/s2)