Heat And Thermodynamics

Let \(\eta_{1}\) is the efficiency of an engine at \(T_{1}=447^{\circ} \mathrm{C}\) and \(\mathrm{T}_{2}=147^{\circ} \mathrm{C}\) while \(\eta_{2}\) is the efficiency at \(\mathrm{T}_{1}=947^{\circ} \mathrm{C}\) and \(\mathrm{T}_{2}=47^{\circ} \mathrm{C}\) The ratio \(\frac{\eta_{1}}{\eta_{2}}\) will be :