16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4ee,{"@context":"https://schema.org","@type":"Quiz","name":"Jee Main 2022 Gravitation PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/jee-main/questions/2022/physics/gravitation/1l6f55tlh","educationalLevel":"Entrance exam preparation","about":"Jee Main / Physics / Gravitation","hasPart":{"@type":"Question","name":"Jee Main 2022 Gravitation PYQ with Solution","text":"An object is taken to a height above the surface of earth at a distance {5 \\over 4} R from the centre of the earth. Where radius of earth, R = 6400 km. The percentage decrease in the weight of the object will be :","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"A"},"comment":{"@type":"Comment","text":"The weight of an object at a distance d from the center of the Earth is given by: W' = W \\left(\\frac{R}{d}\\right)^2 where: W' is the weight at distance d, W is the weight at the Earth's surface, R is the radius of the Earth, d is the distance from the center of the Earth. In this problem, we are asked to find the percentage decrease in weight, which can be calculated by: \\Delta W = \\frac{W - W'}{W} \\times 100\\% where ΔW is the percentage change in weight. Substituting the weight..."}}}18:T4c8,

The weight of an object at a distance d from the center of the Earth is given by:

$$W' = W \left(\frac{R}{d}\right)^2$$

where:

W' is the weight at distance d,
W is the weight at the Earth's surface,
R is the radius of

Gravitation

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