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Limits Continuity And Differentiability

JEE Main 2022 (Online) 25th July Morning Shift

MCQ+4 / -12022

If \(\mathop {\lim }\limits_{n \to \infty } \left( {\sqrt {{n^2} - n - 1} + n\alpha + \beta } \right) = 0\), then \(8(\alpha+\beta)\) is equal to :

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