Jee Main
Limits Continuity And Differentiability
JEE Main 2022 (Online) 29th June Evening Shift
MCQ+4 / -12022
The value of \(\mathop {\lim }\limits_{x \to 1} {{({x^2} - 1){{\sin }^2}(\pi x)} \over {{x^4} - 2{x^3} + 2x - 1}}\) is equal to:
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