Differentiation

ধর \(x(t) = 2\sqrt 2 \cos t\sqrt {\sin 2t}\) এবং \(y(t) = 2\sqrt 2 \sin t\sqrt {\sin 2t} ,\,t \in \left( {0,{\pi \over 2}} \right)\) । তাহলে \({{1 + {{\left( {{{dy} \over {dx}}} \right)}^2}} \over {{{{d^2}y} \over {d{x^2}}}}}\) এর \(t = {\pi \over 4}\) এ মান হবে