Jee Main
Vector Algebra
JEE Main 2021 (Online) 31st August Evening Shift
MCQ+4 / -12021
Statement I :
Two forces \(\left( {\overrightarrow P + \overrightarrow Q } \right)\) and \(\left( {\overrightarrow P - \overrightarrow Q } \right)\) where \(\overrightarrow P \bot \overrightarrow Q\), when act at an angle \(\theta\)1 to each other, the magnitude of their resultant is \(\sqrt {3({P^2} + {Q^2})}\), when they act at an angle \(\theta\)2, the magnitude of their resultant becomes \(\sqrt {2({P^2} + {Q^2})}\). This is possible only when \({\theta _1} < {\theta _2}\).
Statement II :
In the situation given above.
\(\theta\)1 = 60\(^\circ\) and \(\theta\)2 = 90\(^\circ\)
In the light of the above statements, choose the most appropriate answer from the options given below :-
Two forces \(\left( {\overrightarrow P + \overrightarrow Q } \right)\) and \(\left( {\overrightarrow P - \overrightarrow Q } \right)\) where \(\overrightarrow P \bot \overrightarrow Q\), when act at an angle \(\theta\)1 to each other, the magnitude of their resultant is \(\sqrt {3({P^2} + {Q^2})}\), when they act at an angle \(\theta\)2, the magnitude of their resultant becomes \(\sqrt {2({P^2} + {Q^2})}\). This is possible only when \({\theta _1} < {\theta _2}\).
Statement II :
In the situation given above.
\(\theta\)1 = 60\(^\circ\) and \(\theta\)2 = 90\(^\circ\)
In the light of the above statements, choose the most appropriate answer from the options given below :-