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Laws Of Motion

JEE Main 2021 (Online) 25th July Evening Shift

MCQ+4 / -12021
A force \(\overrightarrow F = (40\widehat i + 10\widehat j)N\) acts on a body of mass 5 kg. If the body starts from rest, its position vector \(\overrightarrow r\) at time t = 10 s, will be :

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