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Electromagnetic Waves

JEE Main 2021 (Online) 31st August Evening Shift

MCQ+4 / -12021
The magnetic field vector of an electromagnetic wave is given by \(B = {B_0}{{\widehat i + \widehat j} \over {\sqrt 2 }}\cos (kz - \omega t)\); where \(\widehat i,\widehat j\) represents unit vector along x and y-axis respectively. At t = 0s, two electric charges q1 of 4\(\pi\) coulomb and q2 of 2\(\pi\) coulomb located at \(\left( {0,0,{\pi \over k}} \right)\) and \(\left( {0,0,{{3\pi } \over k}} \right)\), respectively, have the same velocity of 0.5 c \(\widehat i\), (where c is the velocity of light). The ratio of the force acting on charge q1 to q2 is :-

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