Jee Main
Atoms And Nuclei
JEE Main 2021 (Online) 27th July Evening Shift
INTEGER+4 / -12021
The K\(\alpha\) X-ray of molybdenum has wavelength 0.071 nm. If the energy of a molybdenum atoms with a K electron knocked out is 27.5 keV, the energy of this atom when an L electron is knocked out will be __________ keV. (Round off to the nearest integer)
[h = 4.14 \(\times\) 10\(-\)15 eVs, c = 3 \(\times\) 108 ms\(-\)1]
[h = 4.14 \(\times\) 10\(-\)15 eVs, c = 3 \(\times\) 108 ms\(-\)1]