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Sets And Relations

JEE Main 2021 (Online) 27th July Evening Shift

MCQ+4 / -12021
Let N be the set of natural numbers and a relation R on N be defined by \(R = \{ (x,y) \in N \times N:{x^3} - 3{x^2}y - x{y^2} + 3{y^3} = 0\}\). Then the relation R is :

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