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JEE Main 2021 (Online) 20th July Morning Shift

INTEGER+4 / -12021
Let y = mx + c, m > 0 be the focal chord of y2 = \(-\) 64x, which is tangent to (x + 10)2 + y2 = 4. Then, the value of 4\(\sqrt 2\) (m + c) is equal to _____________.

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